20=1/2(n^2+4)

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Solution for 20=1/2(n^2+4) equation: 



20=1/2(n^2+4)

We move all terms to the left:

20-(1/2(n^2+4))=0



Domain of the equation: 2(n^2+4))!=0

n∈R



We multiply all the terms by the denominator


-(1+20*2(n^2+4))=0



We calculate terms in parentheses: -(1+20*2(n^2+4)), so:

1+20*2(n^2+4)

determiningTheFunctionDomain
20*2(n^2+4)+1

Wy multiply elements

40n(n+1

Back to the equation:

-(40n(n+1)





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40n(n+1





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40n(n+1





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40n(n+1





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40n(n+1





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40n(n+1





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40n(n+1





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40n(n+1





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40n(n+1





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40n(n+1





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40n(n+1





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40n(n+1





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40n(n+1





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40n(n+1





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